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If AP bisects angle BAC and M is any point on AP,prove that perpendiculars drawn from M to AB and AC are equal. |
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Answer» hat , ∠2 = ∠3 ( AP is a bisector ) const . draw M ⊥ on AP and join to AB on P and similarly in other SIDE M ⊥ AP and join that to AC at Q . we get , ∠1 = ∠4 = To prove - PM = QMproof - in Δ APM and Δ AMQ ∠2 = ∠3 ( GIVEN ) AM = AM ( COMMON ) ∠1 = ∠4 ( by const. ) by ASA Δ APM congruent to Δ AMQ .⇒ PM = QM ( C.P.C.T) |
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