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If area of `DeltaABC (Delta)` and angle C are given and if c opposite to given angle is minimum, thenA. `a = sqrt((2Delta)/(sinC))`B. `b = sqrt((2Delta)/(sinC))`C. `a = (4Delta)/(sinC)`D. `b = (4Delta)/(sin^(2)C)` |
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Answer» Correct Answer - A::B `c^(2) = a^(2) + b^(2) - 2ab cos C` `=(a - b)^(2) + 2ab (1-cos C)` `=(a -b)^(2) + (4Delta)/(sinC) (1-cosC)` For c to be minium, `a = b` Also, `Delta = (1)/(2) ab sin C` `rArr a^(2) = (2Delta)/(sin C) = b^(2)` |
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