1.

If at 100^@C temperature copper possess fcc arrangements. Edge length is xÅ . Then find out approximate density ("g/cm"^3) of Cu at this temperature. (Atomic weight of Cu = 63.55 u)

Answer»

`105/(x^3)`
`211/(x^3)`
`205/(x^3)`
`422/(x^3)`

Solution :For fcc unit cell, Z = 4
`therefore D = (63.5 XX 4)/(6 xx 10^(23) xx x^3 xx 10^(-24)) "g/cm"^3`
`therefored = (63.5 xx 4 xx 10)/(6) "g/cm"^3`.
`therefore d = (423.33)/(x^3) = 422/(x^3)`.


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