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| 1. |
If at 298 K the bond energies of C-H,C-C,C=CandH-H bonds are respectively 414, 347, 615 and 435 kJ mol^(-1), the value of enthalpy change for the reaction given below at 298 K will be H_(2)C=CH_(2)(g)+H_(2)(g)toH_(3)C-CH_(3)(g) |
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Answer» `-250` KJ |
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