1.

If at a pressure of 10^(6) dyne//cm^(2), one gram mole of nitrogen occupies 2xx10^(4) cc volume, the calculate the averageenergy of a nitrogen molecules in erg.(Given avogadro's number =6xx10^(23))

Answer»

`14xx10^(-13)`
`10xx10^(-12)`
`10^(6)`
`2xx10^(6)`

Solution : Average `KE =(1)/(2)mV^(2)_(rms)=(1)/(2)m(3p)/(p)=(1)/(2)(M)/(N)XX(3P)/(p)`
`=(1)/(2)xx(28)/(6XX10^(23))(3xx10^(6))/((1)/(2xx10^(4)))`
`=14xx10^(-13)erg`


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