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If (ax³+bx²-5x+2) has (x+2) as a factor and leaves a remainder 12 when divided by (x-2) , find the values of a and b. |
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Answer» Answer: Let f(x) = ax3 + bx2 - 5X + 2
Since x+2 is a factor of f(x), f(-2) = 0
So, -8a + 4B + 12 = 0
Since the remainder is 12 when f(x) is divided by x-2, f(2) = 12
So, 8a + 4b - 8 = 12
We have the SYSTEM of equations: -8a + 4b = -12 8a + 4b = 20
Add the equations to obtain 8b = 8
b = 1
Since b = 1 and 8a + 4b = 20, 8a + 4 = 20
8a = 16
a = 2 |
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