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If B.B/ nucleon in ""_(3)^(7)Li and ""_(2)He^(4) nuclic are 5.6 Mev and 7.06 MeV, then in the reaction p+""_(3)^(7)Li to 2 ""_(2)^(4) He, energy of proton must be : |
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Answer» 39.2MeV B.E. of `""_(2)He^(4)=4 xx 7.06 =28.24MeV` So. B.E. of 2 `(""_(2)He^(4))=56.48 Mev` ENERGY of protons =56.48-39.20=17.28MeV |
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