1.

If B.B/ nucleon in ""_(3)^(7)Li and ""_(2)He^(4) nuclic are 5.6 Mev and 7.06 MeV, then in the reaction p+""_(3)^(7)Li to 2 ""_(2)^(4) He, energy of proton must be :

Answer»

39.2MeV
28.24MeV
17.28MeV
1.46MeV

Solution :B.E. of `""_(3)Li^(7)=7 xx 5.60 =39.20 MEV`
B.E. of `""_(2)He^(4)=4 xx 7.06 =28.24MeV`
So. B.E. of 2 `(""_(2)He^(4))=56.48 Mev`
ENERGY of protons =56.48-39.20=17.28MeV


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