1.

If barr is any vector then barr =

Answer»

`(barr.BARA^(1))bara+(barr.BARB^(1))barb+(barr.BARC^(1))barc`
`(barr.barc^(1))bara+(barr.barb^(1))barb+(barr.bara^(1))barc`
`(barr.bara^(1))bara-(barr.barb^(1))barb+(barr.barc^(1))barc`
`(bara.bara^(1))bara+(barb.barb^(1))barb+(barc.barc^(1))barc`

ANSWER :A


Discussion

No Comment Found