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If both the length and radius of a metallic wire are doubled then its resistance remainsunchanged. |
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Answer» Solution :False - In LENGTH and radius both are doubled then L. = 2L and A. = 4A and HENCE resistance `R. = (RHO l.)/(A.) = (rho (2l))/((4A)) = 1/2 (rhol)/(A) = R/2` |
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