1.

If C+O_(2)rarrCO_(2)+94.2 kcalH_(2)+(1)/(2)O_(2)rarrH_(2)O+68.3 kcalCH_(4)+2O_(2)rarrCO_(2)+2H_(2)O+210.8 kcal

Answer»


Solution :`C+O_(2)rarrCO_(2)+94.2 " KCAL...(i)"`
`H_(2)+(1)/(2)O_(2)rarrH_(2)O+68.3 " kcal...(ii)"`
On multiplication of eq. (ii) by 2 and than ADDING in eq. (i)
`C+2H_(2)+2O_(2)rarrCO_(2)+2H_(2)O+230.8 " kcal...(iii)"`
On SUBTRACTING eq. (iii) by following eq.
`CH_(4)+2O_(2)rarrCO_(2)+2H_(2)O+210.8" kcal. we get,"`
`C+2H_(2)rarrCH_(4)DeltaH=20 kcal`.


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