1.

If CH_3COOH+OH^-=CH_3COO^-+H_2O+q_1 and H^+ OH^-=H_2O+q_2 then the enthalpy change for the reaction, CH_3COOH=CH_3COO^(-)+H^+, is equal to:

Answer»

`q_1+q_2`
`q_1-q_2`
`q_2-q_1`
`-q_1-q_2`

ANSWER :B


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