1.

If CI_2 is passed through hot aqueous NaOH, the products formed have CI in different oxidation states. These are indicated as

Answer»

`-1 and + 1`
`-1 and + 5`
`+ 1 and + 5`
`-1 and + 3`

Solution :With hot and concentrated aqueous NaOH (THOUGH .concentrated. was not MENTIONED in the question PAPER, HOWEVER, it should have been), `Cl_2` reacts as below :
`underset(("hot, conc."))(3overset(0)(Cl_2) + 6NaOH) to underset(("Sodium chloride"))(5Na overset(-1)(Cl)) + underset(("sodium chlorate"))(Naoverset(+5)(Cl)O_3) +3H_2O`


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