1.

If class-mark is 10 and class width is 6, then find the class.

Answer»

Let the upper class limit be x and the lower class limit be y. 

Class mark = 10 …[Given] 

Class-mark = (Lower class limit + Upper class limit)/2

∴ 10 = (x + y)/2

∴ x + y = 20 …(i) 

Class width = 6 … [Given] 

Class width = Upper class limit – Lower class limit 

∴ x – y = 6 …(ii) 

Adding equations (i) and (ii), 

x + y = 20 

x – y = 6

2x = 26 

∴ x = 13 

Substituting x = 13 in equation (i), 

13 + y = 20 

∴ y = 20 – 13 

∴ y = 7 

∴ The required class is 7 – 13.


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