1.

If CO_(2) gas is passed through 500 ml of 0.5 (M) Ca(OH)_(2), the amount of CaCO_(3) produced is

Answer»

10 G
20 g
50 g
25 g

Solution :By equating the equivalents
`W/100xx2=(500xx0.5xx2)/1000`
`W=25 g""(W="mass of "CaCO_(3))`


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