1.

If concentration is expressed as mol L^(-), the equilibrium constant, K for the reaction :2N_(2)O_(5)(g)hArr 4NO_(2)(g)+O_(2)(g)has the units :

Answer»

`mol^(3)L^(-3)`
`mol L^(-1)`
`mol^(3)L^(-1)`
no units.

Solution :`K=([NO_(2)]^(4)[O_(2)])/([N_(2)O_(5)]^(2))=((mol//L)^(4)(mol//L))/((mol//L)^(2))`
`= mol^(3)L^(-3)`


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