1.

If Cos^(-1)x+Cos^(-1)y+Cos^(-1)z=pi,"then "x^(2)+y^(2)+z^(2)+2xyz=

Answer»

`X^(2)+y^(2)+Z^(2)+xyz=0`
`x^(2)+y^(2)+z^(2)+2xyz=0`
`x^(2)+y^(2)+z^(2)+xyz=1`
`x^(2)+y^(2)+z^(2)+2xyz=1`

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