1.

If `cos^(2)alpha+cos^(2)beta=2`, then the value of `tan^(3)alpha+sin^(5)beta` isA. `-1`B. `0`C. `1`D. `(1)/(sqrt(3))`

Answer» Correct Answer - b
`cos^(2)alpha+cosbeta=2`
Put value of `alpha=beta=0^(@)`
`rArrcos^(2)0^(@)+cos^(2)0^(@)=2`
`rArr(1)^(2)+(1)^(2)=2`
`rArr2=2` [it satisfies the equation]
`=tan^(2)alpha+sin^(3)beta`
`=tan^(2)alpha+sin^(2)beta`
`=tan^(2)0^(@)+sin^(2)0^(@)`
`=0+0=0`


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