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If `cos 3x+sin (2x-(7pi)/6)=-2`, then x is equal to `(k in Z)`A. `pi/3 (6k+1)`B. `pi/3 (6k-1)`C. `pi/3 (2k+1)`D. none of these |
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Answer» Correct Answer - D `cos 3x+sin (2x-(7 pi)/6)=-2` `:. Cos 3x=-1` and `sin (2x -(7pi)/6)=-1` or `3x=(2n+1) pi and 2x-(7pi)/6=-pi/2+2 m pi , m, n in Z` or `x=(2n pi)/3+pi/3 and x=mpi+pi/3` or `x=2 kpi +pi/3, k in Z`. |
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