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If cos ^4 theta + sin ^2 theta is equals to M then​

Answer»

cos^4  θ+sin^2  θ=cos^4  θ−cos^2 θ+1=m ∴(cos^2  θ−  1/2)^2 +  3/4 =m     ∴m≥  3/4Maximum VALUE of cosθ=1 ∴m≤  3/4 +(1−  1/2)^2 = 1Hope this HELPS. PLS HIT BRAINIESTTT!!!



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