1.

If (cos (alpha - 3 theta))/( cos^(3) theta)=(sin (alpha - 3 theta))/(sin^(3) theta) = m then

Answer»

`cos 2 ALPHA = (2 m^(2) - 9 m^(2) + 8)/( m^(2))`
`cos alpha = ( 2 - m^(2))/( m)`
`cos 2 alpha = (2 m^(2) + 9 m ^(2) + 8)/( m^(2))`
`cos alpha = ( 2 + m^(2))/(m)`

ANSWER :A::B


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