1.

If(cos(alpha-3theta))/(cos^(3)theta)=(sin(alpha-3theta))/(sin^(3)theta)=m then

Answer»

`cos2 alpha=(2M^(2)-9M^(2)+8)/(m^(2))`
`COS alpha=(2-m^(2))/m`
`cos 2 alpha=(2m^(2)+9m^(2)+8)/(m^(2))`
`cos alpha=(2+m^(2))/m`

Answer :A::B


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