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If cos B=1/3 then find tan B and cosec Aplease answer fast it's urgent |
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Answer» -Cos B = 1/3 = B/HB = 1 and H = 3.By Pythagoras theroem,( H )² = (B)² + (P)²( 3)² = (1)² + (P)²( P )² = 9 - 1P² = 8P = √8 = √2 × 2 × 2P = 2√2.Therefore,TAN B = P/B = 2√2/1 = 2√2Cosec B = H/P = 3/2√2HOPE, IT'S HELP YOUPLZ, MARK ME AS A BRAINLIEST AND GIVE ME THANKSGOOD BYESEE U AGAIN |
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