1.

If cos p = \(\frac{1}7\) and cos Q = \(\frac{13}{14}\),where P and Q both are acute angles. Then, the value of P – Q isA. \(\frac{π}6\)B. \(\frac{π}3\)C. \(\frac{π}4\)D.\(\frac{5π}{12}\)

Answer»

cos p = \(\frac{1}7\),sin P = \(\frac{\sqrt{48}}7\)

cos Q = \(\frac{13}{14}\),sin Q = \(\frac{\sqrt{27}}{14}\)

Cos(p-q) = cos(p)cos(q) + sin(p)sin(q)

cos P -Q = \(\frac{1}2\)

P - Q = \(\frac{π}3\)



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