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| 1. |
If cos theta = 3\5, evaluate sin theta - cos theta/2 tan theta |
| Answer» COS © =3/5=b/h ,LET b= 3k and h=5k , therefore p = 4k by Pythagoras THEOREM p=√h^2-b^2(sin © - cos © )/2 tan ©(4/5 - 3/5 )/2 X 4/3(1/3)/8/3(1 X 3)/(8 X3)1/8 answer | |