1.

If cos(theta - alpha)=a, cos(theta-beta)=b, then sin^(2)(alpha -beta) + 2abcos(alpha-beta)=0

Answer»

`a^(2)+B^(2)`
`a^(2)-b^(2)`
`b^(2)-a^(2)`
`-a^(2)-b^(2)`

ANSWER :A


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