1.

IF cos theta ne 0, and sec theta-1=(sqrt2-1) tan theta then theta=

Answer»

`theta = {(2 N PI)/(3), n in Z}cup{2 n pi + (pi)/(2), n in Z}`
`theta = {2 n pi,n in Z}cup {2 n pi + (pi)/(4) , n inZ}`
`theta = {(2 n pi)/(5), n in Z}cup {2 n pi + (pi)/(6), n in Z}`
`theta = {(2 n pi)/( 7), n in Z} cup {2 n pi + (pi)/(3) , n in Z}`

Answer :B


Discussion

No Comment Found