InterviewSolution
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If `cos28^0+sin28^0=k^3, t h e ncos17^0`is equal to`(k^3)/(sqrt(2))`(b) `-(k^3)/(sqrt(2))`(c) `+-(k^3)/(sqrt(2))`(d) none of theseA. `(k^(3))/sqrt(2)`B. `-(k^(3))/sqrt(2)`C. `+-(k^(3))/sqrt(2)`D. none of these. |
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Answer» Correct Answer - A `cos17^(@)=cos(45^(@)-28^(@))` `cos45^(@)cos28^(@)+sin45^(@)sin28^(@)` `=(cos 28^(@)+sin 28^(@))/(sqrt(2))=(k^(3))/(sqrt(2))` |
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