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If cotθ=7/8,then(1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ) |
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Answer» -STEP EXPLANATION:Given is cotθ=7/8 ⇒ OPPOSITE side = 8 and adjacent side=7 so, HYPOTENUSE will be squareroot of SUM of sqaures of 7 and 8 i.e sqrt7^2+8^2=√113 so now sinθ=8/√113 and cosθ=7/√113(1+sinθ)(1-sinθ)/(1+cotθ)(1-cosθ)=1-sin^2θ/1+cotθ(1-cosθ) = 1-64/113/1+7/8(1-7/√113)on solving we get 49/(√113-7)√113 |
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