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`If``cottheta=(15)/8,t h e ne v a l u a t e((2+2sintheta)(1-sintheta)/((1+costheta)(2-2costheta)` |
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Answer» Given expression `=((2+2 sin theta)(1-sin theta))/((1+cos theta )(2-2cos theta ))` `=(2(1+sin theta )(1-sin theta))/(2(1+cos theta )(1-cos theta))` `=((1-sin^(2)theta ))/((1-cos ^(2)theta ))=(cos^(2) theta)/(sin^(2) theta)= cot ^(2)theta` `=( cot theta)^(2)=((15)/(8))^(2)=(225)/(64).` Hence , the value of the given expression is `(225)/(64).` |
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