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If cotx=3/4,x in 2nd quadrant,then find sinx/2,cosx/2,tanx/2 |
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Answer» -step explanation:cotx = base/perpendicular =3/4therefore base= 3 and perpendicular is 4by using Pythagoras theorembase²+perpendicular ²= hypotenuse ²( 3²+4²) = h²( 9 + 16) = h²25 = h². h = 5sinx = p/ h = 4/5/2 = 2/5 2cosx = b/h = 3/5/2= -3/10 22tanx. = p/b = 2×4/3/2= -4/3 2 cos and TAN are negative in second quadrant |
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