If d is the HCF of 56 and 72, find x, y satisfying d = 56x + 72y. Also – InterviewSolution

1.

If d is the HCF of 56 and 72, find x, y satisfying d = 56x + 72y. Also show that x and y is not unique.

Answer»

$d = 8$

$8 = 56x + 72y$

$8 = 8(7x + 9y)$

$1 = 7x + 9y$

$7x = 1 - 9y$

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