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If d is the HCF of 88 and 56, then find x and y satisfying d=88x+56y, where x and y are integers. Also, show that x and y are not unique

Answer» If d is the HCF of 88 and 56, then find x and y satisfying d=88x+56y, where x and y are integers. Also, show that x and y are not unique


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