If d is the HCF of 92 and 56, then find x satisfying d= 92x +56×5. – InterviewSolution

1.	If d is the HCF of 92 and 56, then find x satisfying d= 92x +56×5.
Answer» If d is the HCF of 92 and 56, then find x satisfying d= 92x +56×5.

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