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If d1 and d2 (d2 > d1) are the diameters of two concentric circles and C is the length of a chord of a circle which is tangent to the order circle, prove that d22=c24+d21.

Answer» If d1 and d2 (d2 > d1) are the diameters of two concentric circles and C is the length of a chord of a circle which is tangent to the order circle, prove that d22=c24+d21.


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