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If `**` defined on the set `{1, 2, 3, 4, 5}` by `a**b = LCM`of `a` and `b` a binary operation? Justify your answer. |
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Answer» Given set A = { 1,2,3,4,5} Now `2,3 in A` and 2*3 = L.C.M of 2 and 3 = `6 notinA` `therefore` In the give set, the operation *is not binary. |
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