1.

If degree of dissociation of HI is 0.1 then K_(P) for reaction is: 2HI (g) Harr H_(2) (g) + I_(2) (g)

Answer»

`(1)/(9)`
`(1)/(324)`
`(10)/(36)`
can't be determined

Solution :`{:(,2HI,HARR,H_(2),+,I_(2),,),("moles",a_(0) - a_(0) alpha,,(a_(0) alpha)/(2),,(a_(0) alpha)/(2),alpha = 0.1 "(given)",),(" at" eq^(m),,,,,,,):}`
`K_(p) = K_(C )` as `(DELTA n)_(g) = 0`
`K_(P) = (alpha^(2))/(4 (1 - alpha)^(2)) = ((0.1)^(2))/(4(1 - 0.1)^(2)) = ((0.1)^(2))/(4 xx (0.9)^(2))`
`= (1)/(81 xx 4)`
`K_(P) = (1)/(324)`


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