1.

If Delta_(f)G^(@) for NH_(3)(g) is - 16.4 kJ mol^(-1), then Delta G^(@) for the reaction : N_(2)(g) + 3 H_(2)(g) rarr 2NH_(3)(g) is

Answer»

`32.8 KJ MOL^(-1)`
`16.4 kJ mol^(-1)`
`- 16.4 kJ mol^(-1)`
`- 32.8 kJ mol^(-1)`

ANSWER :D


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