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If `Delta_(f)H^(@)(C_(2)H_(4))` and `Delta_(f)H^(@)(C_(2)H_(6))` are `x_(1)` and `x_(2)` kcal `mol^(-1)`, then heat of hydrogenation of `C_(2)H_(4)` is :A. `x_(1) + x_(2)`B. `x_(1) - x_(2)`C. `x_(2) - x_(1)`D. `x_(1) + 2x_(2)` |
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Answer» Correct Answer - C `C_(2)H_(4)(g)+H_(2)(g)rarrC_(2)H_(6)(g)` `Delta_(r )H=x_(2)-x_(1)` |
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