If `Delta H_("vap")` of pure water at `100^(@)C` is `40.627 kJ mol^(-1)`. The value of `Delta S_("vap")` isA. `10.8 91 kJ mol^(-1)`B. `108.91 Jk^(-1) mol^(-1)`C. `606.27 JK^(-1) mol^(-1)`D. `808.27 JK^(-1) mol^(-1)`

If `Delta H_("vap")` of pure water at `100^(@)C` is `40.627 kJ mol^(-1

1.	If `Delta H_("vap")` of pure water at `100^(@)C` is `40.627 kJ mol^(-1)`. The value of `Delta S_("vap")` isA. `10.8 91 kJ mol^(-1)`B. `108.91 Jk^(-1) mol^(-1)`C. `606.27 JK^(-1) mol^(-1)`D. `808.27 JK^(-1) mol^(-1)`
Answer» Correct Answer - B `DeltaS=(DeltaH)/(T)`

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If `Delta H_("vap")` of pure water at `100^(@)C` is `40.627 kJ mol^(-1)`. The value of `Delta S_("vap")` isA. `10.8 91 kJ mol^(-1)`B. `108.91 Jk^(-1) mol^(-1)`C. `606.27 JK^(-1) mol^(-1)`D. `808.27 JK^(-1) mol^(-1)`

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