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If DeltaH_f^@" for " H_2O and H_2O_2 " are " -280 and -188 kJ mol^(-1), the enthalpy change for the reaction, 2 H_2O_2 (l) to 2H_2O (l) + O_2(g) is : |
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Answer» `-196 KJ mol^(-1)` |
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