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If distance between source and screen increases by 2%, then intensity obtained at screen will be ....... |
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Answer» <P> INCREASED by 4% `:. I prop (I)/(r^(2))` `:. (I_(2))/(I_(1))=((r_(1))/(r_(2)))^(2)` but `r_(1)=r` `2% "of" r_(2)=r_(1)+r_(1)` `=((r)/(1.02r))^(2) "" =r+rxx0.02` `=1.02r ` `=((1)/(1.02))^(2)` `=0.96` `:. I_(2)=0.96 I_(1) ""I_(1) gt I_(2)` `(I_(1)-I_(2))/(I_(1))xx100=(1-096I_(1))/(I_(1))xx100%` `=0.04xx100%=` decreasesed by 4 |
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