1.

If due to any reason, the orbital speed of a satellite increases 41.4%. Then in this situation would the satellite escape? Explain.

Answer»

Orbital velocity of the satellite = v0
When any hour, its orbital velocity is increases by 41.4% then the new value of orbital velocity
v’0 = v0 + \(\frac{41.4}{100} v_{0}=v_{0}\left[1+\frac{41.4}{100}\right]\)
= v0 [1 + 0.414]
= v0 × 1.414 = v0\(\sqrt{2}\)
or v’0 = ve (escape velocity)
Therefore, the satellite will escape.



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