If dydx=xyx2+y2;y(1)=1; then a value of x satisfying y(x)=e is: – InterviewSolution

InterviewSolution

1.	If dydx=xyx2+y2;y(1)=1; then a value of x satisfying y(x)=e is:
Answer» If $\frac{d y}{d x} = \frac{x y}{x^{2} + y^{2}}; y (1) = 1;$ then a value of $x$ satisfying $y (x) = e$ is:

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