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If E_(1)=0.5V corresponds to Cr^(3)+3e^(-)rarr Cr_((s)) and E_(2)=0.41V corresponds to Cr^(3+)+e rarr Cr^(2+) reactions, calculate the emf (E_(3)) of the reaction Cr^(2+)+e rarr Cr^(2+) reactions, calculate the emf (E_(3)) of the reaction Cr^(2+)+2e rarr Cr_((s)) |
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Answer» Solution :0.655V HINT : `E_(3)=(3E_(1)-E_(2))/(2)` |
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