1.

If E_(Cd)^(0) = 0.408 V and E_(Ag)^(0) = -799 V, the emf of the cell Cd| Cd^(2+) || Ag^(+) | Ag is

Answer»

`-1.207` V
`+1.207` V
`-0.391 V `
`+0.391 V `

SOLUTION :E CELL = `E_(Cd)^(0) - E_(AG)^(0) = 0.408 - (-0.799) = + 1.207 V`


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