If `E_(Fe^(2+)//Fe)^(@)=-0.440 V` and `E_(Fe^(3+)//Fe^(2+))^(@)=0.770 V`, then `E_(Fe^(3+)//Fe)^(@)` is -A. 0.330 VB. `-0.037 V`C. `-0.330 V`D. `-1.210 V`

If `E_(Fe^(2+)//Fe)^(@)=-0.440 V` and `E_(Fe^(3+)//Fe^(2+))^(@)=0.770

1.	If `E_(Fe^(2+)//Fe)^(@)=-0.440 V` and `E_(Fe^(3+)//Fe^(2+))^(@)=0.770 V`, then `E_(Fe^(3+)//Fe)^(@)` is -A. 0.330 VB. `-0.037 V`C. `-0.330 V`D. `-1.210 V`
Answer» Correct Answer - B `{:(Fe^(+3)//Fe,),(Fe^(+2)+2e^(-) rarr Fe,E^(@)=-0.44),(Fe^(+3)+e^(-) rarr Fe^(+2),E^(@)=0.770),(ulbar(Fe^(+3)+3e^(-) rarr Fe),E^(@)=?):}` `E^(@)=(n_(1)E_(1)^(@)+n_(2)E_(2)^(@))/n_(3)=(2(-0.44)+1xx(0.770))/(3)=(-0.88+0.770)/(3)=-0.037` volt

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If `E_(Fe^(2+)//Fe)^(@)=-0.440 V` and `E_(Fe^(3+)//Fe^(2+))^(@)=0.770 V`, then `E_(Fe^(3+)//Fe)^(@)` is -A. 0.330 VB. `-0.037 V`C. `-0.330 V`D. `-1.210 V`

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