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If `E_(Fe^(2+))^(@)//Fe = -0.441 V` and `E_(Fe^(3+))^(@)//Fe^(2+) = 0.771 V` The standard `EMF` of the reaction `Fe+2Fe^(3+) rarr 3Fe^(2+)` will be:A. 0.330 VB. 1.653 VC. 1.212 VD. 0.111 V |
Answer» Correct Answer - C For the cell reaction `Fe+2Fe^(3+)to3Fe^(2+)` Anode reaction is `Fe to Fe^(2+)+2e^(-)` Cathode reaction is `2Fe^(3+)+2e to 2Fe^(2+)` `E_(cell)^(@)=E_(Cathode)^(@)-E_(Anode)^(@)(E^(@)"is reduction potential")`ltbrge0.771-(-0.441) `E_(Cell)^(@)=1.212 V` |
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