1.

If E_((Fe^(2+)|Fe))^(o)=-0.441V and E_((Fe^(3+)|Fe^(2+)))^(o)=0.771V, then what is emf for following reaction ? [Fe+2Fe^(3+) to 3Fe^(2+)].

Answer»

1.653
1.212 V
0.111 V
0.330 V

Solution :`Fe^(2+)+2e^(-) to Fe,""E_(1)^(o)=-0.414V`
`Fe^(3+)+e^(-) to Fe^(2+),""E_(2)^(o)=0.771V`
Required REACTION : `Fe+2Fe^(3+) to 3Fe^(2+)`
`=(Fe to Fe^(2+)+2e^(-))`. . .(oxidation)
`+(2Fe^(3+)+2e^(-) to 2Fe^(2+))`. . . (reduction)
`E_(CELL)^(o)=E_(Cathode)^(o)-E_("ANODE")^(o)`
`=0.771-(-0.441)`
`E_(cell)^(o)=1.212V`


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