1.

If e/m of electron is 1.76xx10^(11)Ckg^(-11) and the stopping potential is 0.71 V, then the maximum velocity of the photoelectron is

Answer»

a. 150 km `s^(-1)`
b. 200 km `s^(-1)`
c. 500 km `s^(-1)`
d. 250 km `s^(-1)`

ANSWER :C


Discussion

No Comment Found

Related InterviewSolutions