1.

If earth suddenly stops revolving and whole of its K.E. is used up for raising its temperature and if S = specific heat, R = radius, omega = angular velocity of earth, the rise of temperature of earth is : (J = joules constant)

Answer»

`(R^(2)omega^(2))/(5S)`
`(R^(2)omega^(2))/(5J)`
`(R^(2)omega^(2))/(5JS)`
`(R^(2)omega)/(5JS)`

Solution :Here `MStheta=(1)/(2)xx(2)/(5)(MR^(2)omega^(2))/(J)`
`therefore theta=(R^(2)omega^(2))/(5JS)`


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